copy how Lua 5.3 REPL prints expr values

Dependencies

• [2] 6IQOBYPT repl
• [3] R5QXEHUI somebody stop me

Change contents

• edit in mu.lua at line 7
  [2.121]→[2.121:216](∅→∅)
  −

  − -- unclear how Lua (post 5.2) is able to selectively print values of variables

  − -- at the repl
• replacement in mu.lua at line 34
  [2.710]→[2.710:745](∅→∅)
  − local f, err = load(buf, 'REPL')
  [2.710]

  [2.745]
  + local f, err = load('return '..buf, 'REPL')
• replacement in mu.lua at line 47
  [2.1031]→[2.1031:1206](∅→∅)
  − stdscr:addstr(err..'\n')

  − if string.match(err, "'<eof>'$") or string.match(err, "<eof>$") then

  − buf = buf .. '\n'

  − new_expr = false

  − else

  − print(err)
  [2.1031]

  [2.1206]
  + local f, err = load(buf, 'REPL')

  + if f then
• edit in mu.lua at line 51
  [2.1243]

  [2.1243]
  + local success, results = gather_results(xpcall(f, function(...) return debug.traceback() end))

  + if success then

  + for _, result in ipairs(results) do

  + print(result)

  + end

  + else

  + print(results[1])

  + end

  + else

  + stdscr:addstr(err..'\n')

  + if string.match(err, "'<eof>'$") or string.match(err, "<eof>$") then

  + buf = buf .. '\n'

  + new_expr = false

  + else

  + print(err)

  + buf = ''

  + new_expr = true

  + end